공부/Python

Arbitrary-Precision

Pydata Stack을 사용하지 않는 Python의 경우 OverFlow가 발생하지 않을까.

 

In computer science, arbitrary-precision arithmetic, also called bignum arithmetic, multiple precision arithmetic, or sometimes infinite-precision arithmetic, indicates that calculations are performed on numbers whose digits of precision are limited only by the available memory of the host system. (Wikipedia)

Python2의 경우 int와 long이 있었다. 하지만 Python3에서 long이 사라졌다.

Python3의 int와 Python2의 int가 같다면 Overflow는 발생할 것이다. 하지만, PY3의 int가 Arbitrary Precision를 지원하며 Overflow는  사라졌다. 기존의 Fixed-Precision과 작동 방식이 다르다는 것 같다.

 

#ifndef Py_LIMITED_API
#ifndef Py_LONGINTREPR_H
#define Py_LONGINTREPR_H
#ifdef __cplusplus
extern "C" {
#endif


/* This is published for the benefit of "friends" marshal.c and _decimal.c. */

/* Parameters of the long integer representation.  There are two different
   sets of parameters: one set for 30-bit digits, stored in an unsigned 32-bit
   integer type, and one set for 15-bit digits with each digit stored in an
   unsigned short.  The value of PYLONG_BITS_IN_DIGIT, defined either at
   configure time or in pyport.h, is used to decide which digit size to use.

   Type 'digit' should be able to hold 2*PyLong_BASE-1, and type 'twodigits'
   should be an unsigned integer type able to hold all integers up to
   PyLong_BASE*PyLong_BASE-1.  x_sub assumes that 'digit' is an unsigned type,
   and that overflow is handled by taking the result modulo 2**N for some N >
   PyLong_SHIFT.  The majority of the code doesn't care about the precise
   value of PyLong_SHIFT, but there are some notable exceptions:

   - long_pow() requires that PyLong_SHIFT be divisible by 5

   - PyLong_{As,From}ByteArray require that PyLong_SHIFT be at least 8

   - long_hash() requires that PyLong_SHIFT is *strictly* less than the number
     of bits in an unsigned long, as do the PyLong <-> long (or unsigned long)
     conversion functions

   - the long <-> size_t/Py_ssize_t conversion functions expect that
     PyLong_SHIFT is strictly less than the number of bits in a size_t

   - the marshal code currently expects that PyLong_SHIFT is a multiple of 15

   - NSMALLNEGINTS and NSMALLPOSINTS should be small enough to fit in a single
     digit; with the current values this forces PyLong_SHIFT >= 9

  The values 15 and 30 should fit all of the above requirements, on any
  platform.
*/

#if PYLONG_BITS_IN_DIGIT == 30
#if !(defined HAVE_UINT64_T && defined HAVE_UINT32_T &&          \
      defined HAVE_INT64_T && defined HAVE_INT32_T)
#error "30-bit long digits requested, but the necessary types are not available on this platform"
#endif
typedef PY_UINT32_T digit;
typedef PY_INT32_T sdigit; /* signed variant of digit */
typedef PY_UINT64_T twodigits;
typedef PY_INT64_T stwodigits; /* signed variant of twodigits */
#define PyLong_SHIFT	30
#define _PyLong_DECIMAL_SHIFT	9 /* max(e such that 10**e fits in a digit) */
#define _PyLong_DECIMAL_BASE	((digit)1000000000) /* 10 ** DECIMAL_SHIFT */
#elif PYLONG_BITS_IN_DIGIT == 15
typedef unsigned short digit;
typedef short sdigit; /* signed variant of digit */
typedef unsigned long twodigits;
typedef long stwodigits; /* signed variant of twodigits */
#define PyLong_SHIFT	15
#define _PyLong_DECIMAL_SHIFT	4 /* max(e such that 10**e fits in a digit) */
#define _PyLong_DECIMAL_BASE	((digit)10000) /* 10 ** DECIMAL_SHIFT */
#else
#error "PYLONG_BITS_IN_DIGIT should be 15 or 30"
#endif
#define PyLong_BASE	((digit)1 << PyLong_SHIFT)
#define PyLong_MASK	((digit)(PyLong_BASE - 1))

#if PyLong_SHIFT % 5 != 0
#error "longobject.c requires that PyLong_SHIFT be divisible by 5"
#endif

/* Long integer representation.
   The absolute value of a number is equal to
   	SUM(for i=0 through abs(ob_size)-1) ob_digit[i] * 2**(SHIFT*i)
   Negative numbers are represented with ob_size < 0;
   zero is represented by ob_size == 0.
   In a normalized number, ob_digit[abs(ob_size)-1] (the most significant
   digit) is never zero.  Also, in all cases, for all valid i,
   	0 <= ob_digit[i] <= MASK.
   The allocation function takes care of allocating extra memory
   so that ob_digit[0] ... ob_digit[abs(ob_size)-1] are actually available.

   CAUTION:  Generic code manipulating subtypes of PyVarObject has to
   aware that longs abuse  ob_size's sign bit.
*/

struct _longobject {
	PyObject_VAR_HEAD
	digit ob_digit[1];
};

PyAPI_FUNC(PyLongObject *) _PyLong_New(Py_ssize_t);

/* Return a copy of src. */
PyAPI_FUNC(PyObject *) _PyLong_Copy(PyLongObject *src);

#ifdef __cplusplus
}
#endif
#endif /* !Py_LONGINTREPR_H */
#endif /* Py_LIMITED_API */

hg.python.org/cpython/file/f8942b8e6774/Include/longintrepr.h

 

cpython: f8942b8e6774 Include/longintrepr.h

view Include/longintrepr.h @ 85150:f8942b8e6774 merge from 3.3 Increasing test coverage of ftplib. Patch by Muhammad Jehanzeb author Senthil Kumaran date Mon, 12 Aug 2013 22:26:14 -0700 parents 7355550d5357 children 4d62a62ba44d line source #ifndef Py_LIMI

hg.python.org

 

구현 코드이다. 더 공부해서 알아보도록 하자. Python도 결국 말단은 C API일텐데 어떻게 구현을 하였을까.

 

www.quora.com/How-is-a-long-integer-implemented-in-python

 

How is a long integer implemented in python?

Answer (1 of 4): Generally, In programming languages like C or C++, the precision of integers is limited by Arithmetic Logic Unit (ALU) hardware, which typically offers a precision between 8 to 64 bits. However, languages like Python or Ruby have built in

www.quora.com

한자리 씩 계산한듯 하다.